In the figure, not drawn to scale. STUV is a square. UVW is an equilateral triangle and SU is a straight line. Find
- Four-fifths of ∠SXW
- Twice of ∠WUX
(a)
∠VSU = 45° (Right angle)
∠XVU = 60° (Equilateral triangle)
∠SVX
= 90° - ∠XVU
= 90° - 60°
= 30°
∠SXW
= 30° + 45° (Exterior angle of a triangle)
= 75°
Four-fifths of ∠SXW
=
45 x 75°
= 60°
(b)
∠WXU
= 180° - ∠SXW
= 180° - 75°
= 105° (Angles on a straight line)
∠WUX
= 180° - 60° - 105°
= 15° (Angles sum of triangle)
Twice of ∠WUX
= 2 x 15°
= 30°
Answer(s): (a) 60°; (b) 30°