In the figure, not drawn to scale. JKLM is a square. LMN is an equilateral triangle and JL is a straight line. Find
- Two-fifths of ∠JPN
- Thrice of ∠NLP
(a)
∠MJL = 45° (Right angle)
∠PML = 60° (Equilateral triangle)
∠JMP
= 90° - ∠PML
= 90° - 60°
= 30°
∠JPN
= 30° + 45° (Exterior angle of a triangle)
= 75°
Two-fifths of ∠JPN
=
25 x 75°
= 30°
(b)
∠NPL
= 180° - ∠JPN
= 180° - 75°
= 105° (Angles on a straight line)
∠NLP
= 180° - 60° - 105°
= 15° (Angles sum of triangle)
Thrice of ∠NLP
= 3 x 15°
= 45°
Answer(s): (a) 30°; (b) 45°
