Vaidev gave
211 of his coins to Henry,
19 of his remaining coins to Eric and
38 of the rest of his coins to Japheth. He then had 35 coins left. How many coins had he at first?
| Henry |
Remaining coins |
Total |
| 2 u |
9 u |
11 u |
| |
Eric |
Rest of the coins |
|
| |
1 u |
8 u |
|
| |
|
Japheth |
Left |
|
| |
|
3 u |
5 u |
|
| |
|
|
35 |
|
Number of coins that Vaidev had before = 11 u
Number of coins that Vaidev gave to Henry = 2 u
Number of coins that Vaidev gave to Eric = 1 u
Number of coins that Vaidev gave to Japheth = 3 u
Number of coins that Vaidev had left = 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of coins that Vaidev had at first
= 11 u
= 11 u x 7
= 77
Answer(s): 77
