Ahmad gave
19 of his beads to Jenson,
38 of his remaining beads to Xavier and
35 of the rest of his beads to Glen. He then had 28 beads left. How many beads had he at first?
| Jenson |
Remaining beads |
Total |
| 1 u |
8 u |
9 u |
| |
Xavier |
Rest of the beads |
|
| |
3 u |
5 u |
|
| |
|
Glen |
Left |
|
| |
|
3 u |
2 u |
|
| |
|
|
28 |
|
Number of beads that Ahmad had before = 9 u
Number of beads that Ahmad gave to Jenson = 1 u
Number of beads that Ahmad gave to Xavier = 3 u
Number of beads that Ahmad gave to Glen = 3 u
Number of beads that Ahmad had left = 2 u
2 u = 28
1 u = 28 ÷ 2 = 14
Number of beads that Ahmad had at first
= 9 u
= 9 u x 14
= 126
Answer(s): 126
