John gave
29 of his pens to Tommy,
27 of his remaining pens to Ian and
35 of the rest of his pens to Eric. He then had 4 pens left. How many pens had he at first?
Tommy |
Remaining pens |
Total |
2 u |
7 u |
9 u |
|
Ian |
Rest of the pens |
|
|
2 u |
5 u |
|
|
|
Eric |
Left |
|
|
|
3 u |
2 u |
|
|
|
|
4 |
|
Number of pens that John had before = 9 u
Number of pens that John gave to Tommy = 2 u
Number of pens that John gave to Ian = 2 u
Number of pens that John gave to Eric = 3 u
Number of pens that John had left = 2 u
2 u = 4
1 u = 4 ÷ 2 = 2
Number of pens that John had at first
= 9 u
= 9 u x 2
= 18
Answer(s): 18