Fred gave
19 of his coins to John,
38 of his remaining coins to Riordan and
35 of the rest of his coins to Brandon. He then had 22 coins left. How many coins had he at first?
| John |
Remaining coins |
Total |
| 1 u |
8 u |
9 u |
| |
Riordan |
Rest of the coins |
|
| |
3 u |
5 u |
|
| |
|
Brandon |
Left |
|
| |
|
3 u |
2 u |
|
| |
|
|
22 |
|
Number of coins that Fred had before = 9 u
Number of coins that Fred gave to John = 1 u
Number of coins that Fred gave to Riordan = 3 u
Number of coins that Fred gave to Brandon = 3 u
Number of coins that Fred had left = 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of coins that Fred had at first
= 9 u
= 9 u x 11
= 99
Answer(s): 99
