Ivan gave
19 of his coins to Ben,
18 of his remaining coins to Fred and
37 of the rest of his coins to Will. He then had 32 coins left. How many coins had he at first?
| Ben |
Remaining coins |
Total |
| 1 u |
8 u |
9 u |
| |
Fred |
Rest of the coins |
|
| |
1 u |
7 u |
|
| |
|
Will |
Left |
|
| |
|
3 u |
4 u |
|
| |
|
|
32 |
|
Number of coins that Ivan had before = 9 u
Number of coins that Ivan gave to Ben = 1 u
Number of coins that Ivan gave to Fred = 1 u
Number of coins that Ivan gave to Will = 3 u
Number of coins that Ivan had left = 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Number of coins that Ivan had at first
= 9 u
= 9 u x 8
= 72
Answer(s): 72
