Ben gave
19 of his coins to Ethan,
38 of his remaining coins to Seth and
25 of the rest of his coins to Tommy. He then had 12 coins left. How many coins had he at first?
| Ethan |
Remaining coins |
Total |
| 1 u |
8 u |
9 u |
| |
Seth |
Rest of the coins |
|
| |
3 u |
5 u |
|
| |
|
Tommy |
Left |
|
| |
|
2 u |
3 u |
|
| |
|
|
12 |
|
Number of coins that Ben had before = 9 u
Number of coins that Ben gave to Ethan = 1 u
Number of coins that Ben gave to Seth = 3 u
Number of coins that Ben gave to Tommy = 2 u
Number of coins that Ben had left = 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of coins that Ben had at first
= 9 u
= 9 u x 4
= 36
Answer(s): 36
