Pierre gave
19 of his marbles to Julian,
38 of his remaining marbles to Sam and
15 of the rest of his marbles to Elijah. He then had 24 marbles left. How many marbles had he at first?
Julian |
Remaining marbles |
Total |
1 u |
8 u |
9 u |
|
Sam |
Rest of the marbles |
|
|
3 u |
5 u |
|
|
|
Elijah |
Left |
|
|
|
1 u |
4 u |
|
|
|
|
24 |
|
Number of marbles that Pierre had before = 9 u
Number of marbles that Pierre gave to Julian = 1 u
Number of marbles that Pierre gave to Sam = 3 u
Number of marbles that Pierre gave to Elijah = 1 u
Number of marbles that Pierre had left = 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Number of marbles that Pierre had at first
= 9 u
= 9 u x 6
= 54
Answer(s): 54