Perry gave
29 of his coins to Archie,
17 of his remaining coins to Cole and
16 of the rest of his coins to Luke. He then had 25 coins left. How many coins had he at first?
Archie |
Remaining coins |
Total |
2 u |
7 u |
9 u |
|
Cole |
Rest of the coins |
|
|
1 u |
6 u |
|
|
|
Luke |
Left |
|
|
|
1 u |
5 u |
|
|
|
|
25 |
|
Number of coins that Perry had before = 9 u
Number of coins that Perry gave to Archie = 2 u
Number of coins that Perry gave to Cole = 1 u
Number of coins that Perry gave to Luke = 1 u
Number of coins that Perry had left = 5 u
5 u = 25
1 u = 25 ÷ 5 = 5
Number of coins that Perry had at first
= 9 u
= 9 u x 5
= 45
Answer(s): 45