Ivan gave
29 of his coins to Tim,
27 of his remaining coins to Glen and
15 of the rest of his coins to Caden. He then had 40 coins left. How many coins had he at first?
| Tim |
Remaining coins |
Total |
| 2 u |
7 u |
9 u |
| |
Glen |
Rest of the coins |
|
| |
2 u |
5 u |
|
| |
|
Caden |
Left |
|
| |
|
1 u |
4 u |
|
| |
|
|
40 |
|
Number of coins that Ivan had before = 9 u
Number of coins that Ivan gave to Tim = 2 u
Number of coins that Ivan gave to Glen = 2 u
Number of coins that Ivan gave to Caden = 1 u
Number of coins that Ivan had left = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Number of coins that Ivan had at first
= 9 u
= 9 u x 10
= 90
Answer(s): 90
