Vaidev gave
29 of his coins to George,
17 of his remaining coins to Howard and
16 of the rest of his coins to Jeremy. He then had 20 coins left. How many coins had he at first?
| George |
Remaining coins |
Total |
| 2 u |
7 u |
9 u |
| |
Howard |
Rest of the coins |
|
| |
1 u |
6 u |
|
| |
|
Jeremy |
Left |
|
| |
|
1 u |
5 u |
|
| |
|
|
20 |
|
Number of coins that Vaidev had before = 9 u
Number of coins that Vaidev gave to George = 2 u
Number of coins that Vaidev gave to Howard = 1 u
Number of coins that Vaidev gave to Jeremy = 1 u
Number of coins that Vaidev had left = 5 u
5 u = 20
1 u = 20 ÷ 5 = 4
Number of coins that Vaidev had at first
= 9 u
= 9 u x 4
= 36
Answer(s): 36
