Gabriel gave
29 of his coins to Ben,
27 of his remaining coins to Fred and
15 of the rest of his coins to Brandon. He then had 40 coins left. How many coins had he at first?
| Ben |
Remaining coins |
Total |
| 2 u |
7 u |
9 u |
| |
Fred |
Rest of the coins |
|
| |
2 u |
5 u |
|
| |
|
Brandon |
Left |
|
| |
|
1 u |
4 u |
|
| |
|
|
40 |
|
Number of coins that Gabriel had before = 9 u
Number of coins that Gabriel gave to Ben = 2 u
Number of coins that Gabriel gave to Fred = 2 u
Number of coins that Gabriel gave to Brandon = 1 u
Number of coins that Gabriel had left = 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Number of coins that Gabriel had at first
= 9 u
= 9 u x 10
= 90
Answer(s): 90
