Simon gave
29 of his coins to Asher,
27 of his remaining coins to George and
15 of the rest of his coins to Caden. He then had 8 coins left. How many coins had he at first?
| Asher |
Remaining coins |
Total |
| 2 u |
7 u |
9 u |
| |
George |
Rest of the coins |
|
| |
2 u |
5 u |
|
| |
|
Caden |
Left |
|
| |
|
1 u |
4 u |
|
| |
|
|
8 |
|
Number of coins that Simon had before = 9 u
Number of coins that Simon gave to Asher = 2 u
Number of coins that Simon gave to George = 2 u
Number of coins that Simon gave to Caden = 1 u
Number of coins that Simon had left = 4 u
4 u = 8
1 u = 8 ÷ 4 = 2
Number of coins that Simon had at first
= 9 u
= 9 u x 2
= 18
Answer(s): 18
