Luke gave
19 of his marbles to Tom,
18 of his remaining marbles to George and
37 of the rest of his marbles to Sean. He then had 32 marbles left. How many marbles had he at first?
| Tom |
Remaining marbles |
Total |
| 1 u |
8 u |
9 u |
| |
George |
Rest of the marbles |
|
| |
1 u |
7 u |
|
| |
|
Sean |
Left |
|
| |
|
3 u |
4 u |
|
| |
|
|
32 |
|
Number of marbles that Luke had before = 9 u
Number of marbles that Luke gave to Tom = 1 u
Number of marbles that Luke gave to George = 1 u
Number of marbles that Luke gave to Sean = 3 u
Number of marbles that Luke had left = 4 u
4 u = 32
1 u = 32 ÷ 4 = 8
Number of marbles that Luke had at first
= 9 u
= 9 u x 8
= 72
Answer(s): 72
