Dylan gave
16 of his buttons to Pierre,
25 of his remaining buttons to Lee and
13 of the rest of his buttons to Vaidev. He then had 22 buttons left. How many buttons had he at first?
Pierre |
Remaining buttons |
Total |
1 u |
5 u |
6 u |
|
Lee |
Rest of the buttons |
|
|
2 u |
3 u |
|
|
|
Vaidev |
Left |
|
|
|
1 u |
2 u |
|
|
|
|
22 |
|
Number of buttons that Dylan had before = 6 u
Number of buttons that Dylan gave to Pierre = 1 u
Number of buttons that Dylan gave to Lee = 2 u
Number of buttons that Dylan gave to Vaidev = 1 u
Number of buttons that Dylan had left = 2 u
2 u = 22
1 u = 22 ÷ 2 = 11
Number of buttons that Dylan had at first
= 6 u
= 6 u x 11
= 66
Answer(s): 66