Bobby gave
211 of his buttons to Cody,
19 of his remaining buttons to Liam and
18 of the rest of his buttons to Caden. He then had 21 buttons left. How many buttons had he at first?
| Cody |
Remaining buttons |
Total |
| 2 u |
9 u |
11 u |
| |
Liam |
Rest of the buttons |
|
| |
1 u |
8 u |
|
| |
|
Caden |
Left |
|
| |
|
1 u |
7 u |
|
| |
|
|
21 |
|
Number of buttons that Bobby had before = 11 u
Number of buttons that Bobby gave to Cody = 2 u
Number of buttons that Bobby gave to Liam = 1 u
Number of buttons that Bobby gave to Caden = 1 u
Number of buttons that Bobby had left = 7 u
7 u = 21
1 u = 21 ÷ 7 = 3
Number of buttons that Bobby had at first
= 11 u
= 11 u x 3
= 33
Answer(s): 33
