Howard gave
111 of his beads to Sean,
310 of his remaining beads to Carl and
27 of the rest of his beads to Neave. He then had 10 beads left. How many beads had he at first?
| Sean |
Remaining beads |
Total |
| 1 u |
10 u |
11 u |
| |
Carl |
Rest of the beads |
|
| |
3 u |
7 u |
|
| |
|
Neave |
Left |
|
| |
|
2 u |
5 u |
|
| |
|
|
10 |
|
Number of beads that Howard had before = 11 u
Number of beads that Howard gave to Sean = 1 u
Number of beads that Howard gave to Carl = 3 u
Number of beads that Howard gave to Neave = 2 u
Number of beads that Howard had left = 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Number of beads that Howard had at first
= 11 u
= 11 u x 2
= 22
Answer(s): 22
