Howard gave
29 of his buttons to Bobby,
27 of his remaining buttons to George and
35 of the rest of his buttons to Gabriel. He then had 30 buttons left. How many buttons had he at first?
| Bobby |
Remaining buttons |
Total |
| 2 u |
7 u |
9 u |
| |
George |
Rest of the buttons |
|
| |
2 u |
5 u |
|
| |
|
Gabriel |
Left |
|
| |
|
3 u |
2 u |
|
| |
|
|
30 |
|
Number of buttons that Howard had before = 9 u
Number of buttons that Howard gave to Bobby = 2 u
Number of buttons that Howard gave to George = 2 u
Number of buttons that Howard gave to Gabriel = 3 u
Number of buttons that Howard had left = 2 u
2 u = 30
1 u = 30 ÷ 2 = 15
Number of buttons that Howard had at first
= 9 u
= 9 u x 15
= 135
Answer(s): 135
