A motorbike is travelling from Town B to Town C. At 55 km/h, it will arrive five hours later than the scheduled time. At 65 km/h, it will arrive at three hours later than the scheduled time. What is the distance between Town B and Town C?
| |
Faster speed |
Slower speed |
| Speed |
65 km/h |
55 km/h |
| Time |
1 u + 3 |
1 u + 5 |
| Distance |
65 (1 u + 3) =
65 u + 195 |
55 (1 u + 5) =
55 u + 275 |
Distance covered for the faster speed or the slower speed is the same.
65 u + 195 = 55 u + 275
65 u - 55 u = 275 - 195
10 u = 80
1 u = 80 ÷ 10 = 8
Distance between Town B and Town C
= 65 u + 195
= 65 x 8 + 195
= 520 + 195
= 715 km
Answer(s): 715 km
