Lee bought some markers at $6 each. He later sold them to his customers at $9 each. For customers who bought three markers were given another marker for free. The customers bought either one or three markers. Lee gave away 110 free markers and collected a total of $870 more than what he had paid for. How many customers bought just one marker each?
|
Markers sold |
Markers given to customers who got 1 marker each |
Markers given to customers who got 4 markers each |
Number |
1 u |
1 u - 440 |
440 |
Value |
$6 |
$9 |
$9 |
Total Value |
6 u |
9 u - $3960 |
$2970 |
Since 110 markers were given free, there were 110 customers who bought three markers each.
Number of markers that each customer would get if they bought three markers each and got 1 marker free
= 3 + 1
= 4
Total number of markers for customers who each bought three markers
= 4 x 110
= 440
Number of markers for customers who each bought 1 marker = 1 u - 440
Total amount collected from customers who bought 1 marker each
= 9 x (1 u - 440)
= 9 u - 3960
Total amount collected from customers who bought three markers each
= 110 x 3 x 9
= $2970
Total amount collected from all the customers
= 9 u - 3960 + 2970
= 9 u - 990
Lee collected a total of $870 more than what he had paid for.
9 u - 990 = 6 u + 870
9 u - 6 u = 870 + 990
3 u = 1860
1 u = 1860 ÷ 3 = 620
Number of customers who bought just one marker
= 1 u - 440
= 620 - 440
= 180
Answer(s): 180