The figure, not drawn to scale, is made up of 3 identical rectangles, DEFG, HJKL and MNPH. Each rectangle has an area of 82 cm². Point H is the centre of rectangle DEFG.
- What fraction of the figure is unshaded?
- What is the area of the shaded parts?
(a)
If we pivot the rectangle HJKL from point H, we can see that the shaded area is
14 of rectangle HJKL.
Similary, if we pivot the rectangle MNPH from point H, we can see that the shaded area is
14 of rectangle MNPH.
Fraction of the figure that is shaded =
210 =
15 Fraction of the figure that is unshaded
= 1 -
15 =
45 (b)
Area of the shaded parts
= 2 x
14 x 82
= 41 cm
2 Answer(s): (a)
45; (b) 41 cm
2