The figure, not drawn to scale, is made up of 3 identical squares, KLMN, PQRS and TUVP. The length of each square is 6 cm. Point P is the centre of square KLMN.
- What fraction of the figure is shaded?
- What is the area of the unshaded parts?
(a)
If we pivot the square PQRS from point P, we can see that the shaded area is
14 of square PQRS.
Similary, if we pivot the square TUVP from point P, we can see that the shaded area is
14 of square TUVP.
Fraction of the figure that is shaded =
210 =
15 (b)
Fraction of the figure that is unshaded
= 1 -
15 =
45 Area of each square
= 6 x 6
= 36 cm
2 Area of the shaded parts
= 2 x
14 x 36
= 18 cm
2 Area of the unshaded parts
= 4 x 18
= 72 cm
2 Answer(s): (a)
15; (b) 72 cm
2