The figure, not drawn to scale, is made up of 3 identical rectangles, EFGH, JKLM and NPQJ. Each rectangle has an area of 92 cm². Point J is the centre of rectangle EFGH.
- What fraction of the figure is unshaded?
- What is the area of the shaded parts?
(a)
If we pivot the rectangle JKLM from point J, we can see that the shaded area is
14 of rectangle JKLM.
Similary, if we pivot the rectangle NPQJ from point J, we can see that the shaded area is
14 of rectangle NPQJ.
Fraction of the figure that is shaded =
210 =
15 Fraction of the figure that is unshaded
= 1 -
15 =
45 (b)
Area of the shaded parts
= 2 x
14 x 92
= 46 cm
2 Answer(s): (a)
45; (b) 46 cm
2