The figure, not drawn to scale, is made up of 3 identical squares, DEFG, HJKL and MNPH. The length of each square is 31 cm. Point H is the centre of square DEFG.
- What fraction of the figure is shaded?
- What is the area of the unshaded parts?
(a)
If we pivot the square HJKL from point H, we can see that the shaded area is
14 of square HJKL.
Similary, if we pivot the square MNPH from point H, we can see that the shaded area is
14 of square MNPH.
Fraction of the figure that is shaded =
210 =
15 (b)
Fraction of the figure that is unshaded
= 1 -
15 =
45 Area of each square
= 31 x 31
= 961 cm
2 Area of the shaded parts
= 2 x
14 x 961
= 480.5 cm
2 Area of the unshaded parts
= 4 x 480.5
= 1922 cm
2 Answer(s): (a)
15; (b) 1922 cm
2