PSLE
Kimberly had to sew 113 sweaters. She sewed 8 sweaters each day from Monday to Friday and 11 each day on Saturday and Sunday. Starting on a Thursday, on which day of the week did Kimberly finish sewing all the sweaters? Give your answer in number. (Eg Mon = 1)
Number of weekdays that Kimberly sewed on the first week = 2

Number of sweaters that Kimberly completed for from Thursday to Sunday on the first week
= 2 x 8 + 2 x 11 
= 16 + 22
= 38

Number of sweaters left to sew
= 113 - 38
= 75

Number of sweaters that Kimberly could sew per week from second week onwards
= 5 x 8 + 2 x 11
= 40 + 22
= 62

Number of weeks that Kimberly needed to sew 75 sweaters
= 75 ÷ 62
= 1 r 13

Number of days that Kimberly needed to sew 13 sweaters
= 13 ÷ 8
= 1 r 5

Kimberly needed 1 more day to finish sewing the remaining 5 sweaters.

Day of the week that Kimberly completed her sewing
= 1 + 1
= 2 (Tue)

Answer(s): 2