PSLE
Hilda had to sew 114 sweaters. She sewed 6 sweaters each day from Monday to Friday and 11 each day on Saturday and Sunday. Starting on a Monday, on which day of the week did Hilda finish sewing all the sweaters? Give your answer in number. (Eg Mon = 1)
Number of weekdays that Hilda sewed on the first week = 5

Number of sweaters that Hilda completed for from Monday to Sunday on the first week
= 5 x 6 + 2 x 11 
= 30 + 22
= 52

Number of sweaters left to sew
= 114 - 52
= 62

Number of sweaters that Hilda could sew per week from second week onwards
= 5 x 6 + 2 x 11
= 30 + 22
= 52

Number of weeks that Hilda needed to sew 62 sweaters
= 62 ÷ 52
= 1 r 10

Number of days that Hilda needed to sew 10 sweaters
= 10 ÷ 6
= 1 r 4

Hilda needed 1 more day to finish sewing the remaining 4 sweaters.

Day of the week that Hilda completed her sewing
= 1 + 1
= 2 (Tue)

Answer(s): 2