PSLE
Usha had to sew 101 sweaters. She sewed 5 sweaters each day from Monday to Friday and 11 each day on Saturday and Sunday. Starting on a Monday, on which day of the week did Usha finish sewing all the sweaters? Give your answer in number. (Eg Mon = 1)
Number of weekdays that Usha sewed on the first week = 5

Number of sweaters that Usha completed for from Monday to Sunday on the first week
= 5 x 5 + 2 x 11 
= 25 + 22
= 47

Number of sweaters left to sew
= 101 - 47
= 54

Number of sweaters that Usha could sew per week from second week onwards
= 5 x 5 + 2 x 11
= 25 + 22
= 47

Number of weeks that Usha needed to sew 54 sweaters
= 54 ÷ 47
= 1 r 7

Number of days that Usha needed to sew 7 sweaters
= 7 ÷ 5
= 1 r 2

Usha needed 1 more day to finish sewing the remaining 2 sweaters.

Day of the week that Usha completed her sewing
= 1 + 1
= 2 (Tue)

Answer(s): 2