PSLE Four teams of students sold french fries for charity.
They collected $3 for a small cup of french fries and $6 for a big cup of french fries.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team W |
18 |
2 |
Team X |
12 |
9 |
Team Y |
7 |
11 |
- Which of the three teams collected the least money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team Y?
- Team X sold as many cups of french fries as Team Z but collected $18 less. How many small cups of french fries did Team Z sell?
(a)
Amount collected by Team W
= 18 x 3 + 2 x 6
= 54 + 12
= $66
Amount collected by Team X
= 12 x 3 + 9 x 6
= 36 + 54
= $90
Amount collected by Team Y
= 7 x 3 + 11 x 6
= 21 + 66
= $87
Team W collected the least money.
(b)
Amount collected by Team Y = $87
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team X |
12 |
9 |
21 |
$90 |
Team Z |
6 |
15 |
21 |
90 + 18 = $108 |
Since Team X and Team Z sold the same number of cups but Team X collected $18 less, it means that Team Z sold more big cups than Team X.
Difference in the total amount collected between Team X and Team Z = $18
Difference in the amount collected for every one extra big cup sold by Team Z
= 6 - 3
= $3
Number of extra big cups sold by Team Z
= 18 ÷ 3
= 6
Number of small cups sold by Team Z
= 12 - 6
= 6
Answer(s): (a) W; (b) $87; (c) 6