PSLE Four teams of students sold soda for charity.
They collected $7 for a small cup of soda and $9 for a big cup of soda.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team E |
15 |
3 |
Team F |
13 |
8 |
Team G |
6 |
11 |
- Which of the three teams collected the most money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team E?
- Team H sold as many cups of soda as Team E but collected $6 more. How many big cups of soda did Team H sell?
(a)
Amount collected by Team E
= 15 x 7 + 3 x 9
= 105 + 27
= $132
Amount collected by Team F
= 13 x 7 + 8 x 9
= 91 + 72
= $163
Amount collected by Team G
= 6 x 7 + 11 x 9
= 42 + 99
= $141
Team F collected the most money.
(b)
Amount collected by Team E = $132
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team E |
15 |
3 |
18 |
$132 |
Team H |
12 |
6 |
18 |
132 + 6 = $138 |
Since Team H and Team E sold the same number of cups but Team E collected $6 more, it means that Team H sold more big cups than Team E.
Difference in the total amount collected between Team H and Team E = $6
Difference in the amount collected for every one extra big cup sold by Team H
= 9 - 7
= $2
Number of extra big cups sold by Team H
= 6 ÷ 2
= 3
Number of big cups sold by Team H
= 3 + 3
= 6
Answer(s): (a) F; (b) $132; (c) 6