PSLE Four teams of students sold french fries for charity.
They collected $5 for a small cup of french fries and $9 for a big cup of french fries.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team T |
16 |
3 |
Team U |
14 |
8 |
Team V |
6 |
11 |
- Which of the three teams collected the most money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team T?
- Team W sold as many cups of french fries as Team T but collected $28 more. How many big cups of french fries did Team W sell?
(a)
Amount collected by Team T
= 16 x 5 + 3 x 9
= 80 + 27
= $107
Amount collected by Team U
= 14 x 5 + 8 x 9
= 70 + 72
= $142
Amount collected by Team V
= 6 x 5 + 11 x 9
= 30 + 99
= $129
Team U collected the most money.
(b)
Amount collected by Team T = $107
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team T |
16 |
3 |
19 |
$107 |
Team W |
9 |
10 |
19 |
107 + 28 = $135 |
Since Team W and Team T sold the same number of cups but Team T collected $28 more, it means that Team W sold more big cups than Team T.
Difference in the total amount collected between Team W and Team T = $28
Difference in the amount collected for every one extra big cup sold by Team W
= 9 - 5
= $4
Number of extra big cups sold by Team W
= 28 ÷ 4
= 7
Number of big cups sold by Team W
= 3 + 7
= 10
Answer(s): (a) U; (b) $107; (c) 10