PSLE Four teams of students sold french fries for charity.
They collected $4 for a small cup of french fries and $6 for a big cup of french fries.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team Q |
15 |
4 |
Team R |
11 |
8 |
Team S |
7 |
10 |
- Which of the three teams collected the most money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team Q?
- Team T sold as many cups of french fries as Team Q but collected $8 more. How many big cups of french fries did Team T sell?
(a)
Amount collected by Team Q
= 15 x 4 + 4 x 6
= 60 + 24
= $84
Amount collected by Team R
= 11 x 4 + 8 x 6
= 44 + 48
= $92
Amount collected by Team S
= 7 x 4 + 10 x 6
= 28 + 60
= $88
Team R collected the most money.
(b)
Amount collected by Team Q = $84
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team Q |
15 |
4 |
19 |
$84 |
Team T |
11 |
8 |
19 |
84 + 8 = $92 |
Since Team T and Team Q sold the same number of cups but Team Q collected $8 more, it means that Team T sold more big cups than Team Q.
Difference in the total amount collected between Team T and Team Q = $8
Difference in the amount collected for every one extra big cup sold by Team T
= 6 - 4
= $2
Number of extra big cups sold by Team T
= 8 ÷ 2
= 4
Number of big cups sold by Team T
= 4 + 4
= 8
Answer(s): (a) R; (b) $84; (c) 8