PSLE Four teams of students sold french fries for charity.
They collected $6 for a small cup of french fries and $10 for a big cup of french fries.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team Q |
17 |
3 |
Team R |
14 |
7 |
Team S |
8 |
10 |
- Which of the three teams collected the least money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team S?
- Team R sold as many cups of french fries as Team T but collected $28 less. How many small cups of french fries did Team T sell?
(a)
Amount collected by Team Q
= 17 x 6 + 3 x 10
= 102 + 30
= $132
Amount collected by Team R
= 14 x 6 + 7 x 10
= 84 + 70
= $154
Amount collected by Team S
= 8 x 6 + 10 x 10
= 48 + 100
= $148
Team Q collected the least money.
(b)
Amount collected by Team S = $148
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team R |
14 |
7 |
21 |
$154 |
Team T |
7 |
14 |
21 |
154 + 28 = $182 |
Since Team R and Team T sold the same number of cups but Team R collected $28 less, it means that Team T sold more big cups than Team R.
Difference in the total amount collected between Team R and Team T = $28
Difference in the amount collected for every one extra big cup sold by Team T
= 10 - 6
= $4
Number of extra big cups sold by Team T
= 28 ÷ 4
= 7
Number of small cups sold by Team T
= 14 - 7
= 7
Answer(s): (a) Q; (b) $148; (c) 7