PSLE Four teams of students sold french fries for charity.
They collected $5 for a small cup of french fries and $7 for a big cup of french fries.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team A |
18 |
3 |
Team B |
11 |
9 |
Team C |
9 |
10 |
- Which of the three teams collected the least money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team C?
- Team B sold as many cups of french fries as Team D but collected $10 less. How many small cups of french fries did Team D sell?
(a)
Amount collected by Team A
= 18 x 5 + 3 x 7
= 90 + 21
= $111
Amount collected by Team B
= 11 x 5 + 9 x 7
= 55 + 63
= $118
Amount collected by Team C
= 9 x 5 + 10 x 7
= 45 + 70
= $115
Team A collected the least money.
(b)
Amount collected by Team C = $115
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team B |
11 |
9 |
20 |
$118 |
Team D |
6 |
14 |
20 |
118 + 10 = $128 |
Since Team B and Team D sold the same number of cups but Team B collected $10 less, it means that Team D sold more big cups than Team B.
Difference in the total amount collected between Team B and Team D = $10
Difference in the amount collected for every one extra big cup sold by Team D
= 7 - 5
= $2
Number of extra big cups sold by Team D
= 10 ÷ 2
= 5
Number of small cups sold by Team D
= 11 - 5
= 6
Answer(s): (a) A; (b) $115; (c) 6