PSLE Four teams of students sold soda for charity.
They collected $3 for a small cup of soda and $6 for a big cup of soda.
The table shows the number of cups sold by three of the teams.
|
Small cups |
Big cups |
Team Q |
15 |
3 |
Team R |
14 |
9 |
Team S |
7 |
10 |
- Which of the three teams collected the most money? Give your answer in letter. (Eg A)
- What was the amount of money collected by Team Q?
- Team T sold as many cups of soda as Team Q but collected $6 more. How many big cups of soda did Team T sell?
(a)
Amount collected by Team Q
= 15 x 3 + 3 x 6
= 45 + 18
= $63
Amount collected by Team R
= 14 x 3 + 9 x 6
= 42 + 54
= $96
Amount collected by Team S
= 7 x 3 + 10 x 6
= 21 + 60
= $81
Team R collected the most money.
(b)
Amount collected by Team Q = $63
(c)
|
Small cups |
Big cups |
Total cups |
Total amount |
Team Q |
15 |
3 |
18 |
$63 |
Team T |
13 |
5 |
18 |
63 + 6 = $69 |
Since Team T and Team Q sold the same number of cups but Team Q collected $6 more, it means that Team T sold more big cups than Team Q.
Difference in the total amount collected between Team T and Team Q = $6
Difference in the amount collected for every one extra big cup sold by Team T
= 6 - 3
= $3
Number of extra big cups sold by Team T
= 6 ÷ 3
= 2
Number of big cups sold by Team T
= 3 + 2
= 5
Answer(s): (a) R; (b) $63; (c) 5