PSLE Marion and Roshel folded paper balls over two days. On Monday, Marion folded 22 paper balls more than Roshel. On Tuesday, Marion folded another 14 paper balls and Roshel folded another 1. At the end of the two days, Marion made
79 of the total number of balls. What was the number of paper balls that Roshel folded?
|
Marion |
Roshel |
Difference |
Before |
1 u + 22 |
1 u |
22 |
Change |
+ 14 |
+ 1 |
|
After |
1 u + 36 |
1 u + 1 |
35 |
Comparing between Marion and Roshel in the end |
7 p |
2 p |
5 p |
Difference between the number of paper balls that Marion and Roshel folded in the end is repeated.
Difference between the number of paper balls that Marion and Roshel folded in the end
= 7 p - 2 p
= 5 p
Difference between the number of paper balls that Marion and Roshel folded in the end
= (1 u + 36) - (1 u + 1)
= 1 u + 36 - 1 u - 1
= 36 - 1
= 35
5 p = 35
1 p = 35 ÷ 5 = 7
Number of paper balls that Roshel folded
= 2 p
= 2 x 7
= 14
Answer(s): 14