PSLE Min and Gabby folded paper stars over two days. On Monday, Min folded 27 paper stars more than Gabby. On Tuesday, Min folded another 16 paper stars and Gabby folded another 1. At the end of the two days, Min made
57 of the total number of stars. What was the number of paper stars that Min folded?
|
Min |
Gabby |
Difference |
Before |
1 u + 27 |
1 u |
27 |
Change |
+ 16 |
+ 1 |
|
After |
1 u + 43 |
1 u + 1 |
42 |
Comparing between Min and Gabby in the end |
5 p |
2 p |
3 p |
Difference between the number of paper stars that Min and Gabby folded in the end is repeated.
Difference between the number of paper stars that Min and Gabby folded in the end
= 5 p - 2 p
= 3 p
Difference between the number of paper stars that Min and Gabby folded in the end
= (1 u + 43) - (1 u + 1)
= 1 u + 43 - 1 u - 1
= 43 - 1
= 42
3 p = 42
1 p = 42 ÷ 3 = 14
Number of paper stars that Min folded
= 5 p
= 5 x 14
= 70
Answer(s): 70