PSLE Mary and Sabrina folded paper stars over two days. On Wednesday, Mary folded 5 paper stars more than Sabrina. On Thursday, Mary folded another 37 paper stars and Sabrina folded another 2. At the end of the two days, Mary made
79 of the total number of stars. What was the number of paper stars that Sabrina folded?
|
Mary |
Sabrina |
Difference |
Before |
1 u + 5 |
1 u |
5 |
Change |
+ 37 |
+ 2 |
|
After |
1 u + 42 |
1 u + 2 |
40 |
Comparing between Mary and Sabrina in the end |
7 p |
2 p |
5 p |
Difference between the number of paper stars that Mary and Sabrina folded in the end is repeated.
Difference between the number of paper stars that Mary and Sabrina folded in the end
= 7 p - 2 p
= 5 p
Difference between the number of paper stars that Mary and Sabrina folded in the end
= (1 u + 42) - (1 u + 2)
= 1 u + 42 - 1 u - 2
= 42 - 2
= 40
5 p = 40
1 p = 40 ÷ 5 = 8
Number of paper stars that Sabrina folded
= 2 p
= 2 x 8
= 16
Answer(s): 16