PSLE Kimberly and Tiffany folded paper balls over two days. On Wednesday, Kimberly folded 29 paper balls more than Tiffany. On Thursday, Kimberly folded another 29 paper balls and Tiffany folded another 8. At the end of the two days, Kimberly made
79 of the total number of balls. What was the number of paper balls that Tiffany folded?
|
Kimberly |
Tiffany |
Difference |
Before |
1 u + 29 |
1 u |
29 |
Change |
+ 29 |
+ 8 |
|
After |
1 u + 58 |
1 u + 8 |
50 |
Comparing between Kimberly and Tiffany in the end |
7 p |
2 p |
5 p |
Difference between the number of paper balls that Kimberly and Tiffany folded in the end is repeated.
Difference between the number of paper balls that Kimberly and Tiffany folded in the end
= 7 p - 2 p
= 5 p
Difference between the number of paper balls that Kimberly and Tiffany folded in the end
= (1 u + 58) - (1 u + 8)
= 1 u + 58 - 1 u - 8
= 58 - 8
= 50
5 p = 50
1 p = 50 ÷ 5 = 10
Number of paper balls that Tiffany folded
= 2 p
= 2 x 10
= 20
Answer(s): 20