PSLE Cathy and Marion folded paper stars over two days. On Friday, Cathy folded 27 paper stars more than Marion. On Saturday, Cathy folded another 13 paper stars and Marion folded another 16. At the end of the two days, Cathy made
58 of the total number of stars. What was the number of paper stars that Marion folded?
|
Cathy |
Marion |
Difference |
Before |
1 u + 27 |
1 u |
27 |
Change |
+ 13 |
+ 16 |
|
After |
1 u + 40 |
1 u + 16 |
24 |
Comparing between Cathy and Marion in the end |
5 p |
3 p |
2 p |
Difference between the number of paper stars that Cathy and Marion folded in the end is repeated.
Difference between the number of paper stars that Cathy and Marion folded in the end
= 5 p - 3 p
= 2 p
Difference between the number of paper stars that Cathy and Marion folded in the end
= (1 u + 40) - (1 u + 16)
= 1 u + 40 - 1 u - 16
= 40 - 16
= 24
2 p = 24
1 p = 24 ÷ 2 = 12
Number of paper stars that Marion folded
= 3 p
= 3 x 12
= 36
Answer(s): 36