PSLE
Min and Shannon folded paper stars over two days. On Tuesday, Min folded 58 paper stars more than Shannon. On Wednesday, Min folded another 19 paper stars and Shannon folded another 7. At the end of the two days, Min made ⁷₉ of the total number of stars. What was the number of paper stars that Shannon folded?

	Min	Shannon	Difference
Before	1 u + 58	1 u	58
Change	+ 19	+ 7
After	1 u + 77	1 u + 7	70
Comparing between Min and Shannon in the end	7 p	2 p	5 p

Difference between the number of paper stars that Min and Shannon folded in the end is repeated.

Difference between the number of paper stars that Min and Shannon folded in the end
= 7 p - 2 p
= 5 p

Difference between the number of paper stars that Min and Shannon folded in the end
= (1 u + 77) - (1 u + 7)
= 1 u + 77 - 1 u - 7
= 77 - 7
= 70

5 p = 70

1 p = 70 ÷ 5 = 14

Number of paper stars that Shannon folded
= 2 p
= 2 x 14
= 28

Answer(s): 28