PSLE Cathy and Jane folded paper stars over two days. On Tuesday, Cathy folded 20 paper stars more than Jane. On Wednesday, Cathy folded another 14 paper stars and Jane folded another 1. At the end of the two days, Cathy made
57 of the total number of stars. What was the number of paper stars that Cathy folded?
|
Cathy |
Jane |
Difference |
Before |
1 u + 20 |
1 u |
20 |
Change |
+ 14 |
+ 1 |
|
After |
1 u + 34 |
1 u + 1 |
33 |
Comparing between Cathy and Jane in the end |
5 p |
2 p |
3 p |
Difference between the number of paper stars that Cathy and Jane folded in the end is repeated.
Difference between the number of paper stars that Cathy and Jane folded in the end
= 5 p - 2 p
= 3 p
Difference between the number of paper stars that Cathy and Jane folded in the end
= (1 u + 34) - (1 u + 1)
= 1 u + 34 - 1 u - 1
= 34 - 1
= 33
3 p = 33
1 p = 33 ÷ 3 = 11
Number of paper stars that Cathy folded
= 5 p
= 5 x 11
= 55
Answer(s): 55