PSLE
Jane and Min folded paper stars over two days. On Monday, Jane folded 13 paper stars more than Min. On Tuesday, Jane folded another 36 paper stars and Min folded another 10. At the end of the two days, Jane made ⁵₇ of the total number of stars. What was the number of paper stars that Min folded?

	Jane	Min	Difference
Before	1 u + 13	1 u	13
Change	+ 36	+ 10
After	1 u + 49	1 u + 10	39
Comparing between Jane and Min in the end	5 p	2 p	3 p

Difference between the number of paper stars that Jane and Min folded in the end is repeated.

Difference between the number of paper stars that Jane and Min folded in the end
= 5 p - 2 p
= 3 p

Difference between the number of paper stars that Jane and Min folded in the end
= (1 u + 49) - (1 u + 10)
= 1 u + 49 - 1 u - 10
= 49 - 10
= 39

3 p = 39

1 p = 39 ÷ 3 = 13

Number of paper stars that Min folded
= 2 p
= 2 x 13
= 26

Answer(s): 26