PSLE Abi and Jean folded paper stars over two days. On Wednesday, Abi folded 31 paper stars more than Jean. On Thursday, Abi folded another 24 paper stars and Jean folded another 15. At the end of the two days, Abi made
710 of the total number of stars. What was the number of paper stars that Abi folded?
|
Abi |
Jean |
Difference |
Before |
1 u + 31 |
1 u |
31 |
Change |
+ 24 |
+ 15 |
|
After |
1 u + 55 |
1 u + 15 |
40 |
Comparing between Abi and Jean in the end |
7 p |
3 p |
4 p |
Difference between the number of paper stars that Abi and Jean folded in the end is repeated.
Difference between the number of paper stars that Abi and Jean folded in the end
= 7 p - 3 p
= 4 p
Difference between the number of paper stars that Abi and Jean folded in the end
= (1 u + 55) - (1 u + 15)
= 1 u + 55 - 1 u - 15
= 55 - 15
= 40
4 p = 40
1 p = 40 ÷ 4 = 10
Number of paper stars that Abi folded
= 7 p
= 7 x 10
= 70
Answer(s): 70