PSLE
Jane and Tammy folded paper balls over two days. On Saturday, Jane folded 63 paper balls more than Tammy. On Sunday, Jane folded another 15 paper balls and Tammy folded another 26. At the end of the two days, Jane made ⁷₁₀ of the total number of balls. What was the number of paper balls that Jane folded?

	Jane	Tammy	Difference
Before	1 u + 63	1 u	63
Change	+ 15	+ 26
After	1 u + 78	1 u + 26	52
Comparing between Jane and Tammy in the end	7 p	3 p	4 p

Difference between the number of paper balls that Jane and Tammy folded in the end is repeated.

Difference between the number of paper balls that Jane and Tammy folded in the end
= 7 p - 3 p
= 4 p

Difference between the number of paper balls that Jane and Tammy folded in the end
= (1 u + 78) - (1 u + 26)
= 1 u + 78 - 1 u - 26
= 78 - 26
= 52

4 p = 52

1 p = 52 ÷ 4 = 13

Number of paper balls that Jane folded
= 7 p
= 7 x 13
= 91

Answer(s): 91