PSLE Jade and Gem folded paper balls over two days. On Monday, Jade folded 56 paper balls more than Gem. On Tuesday, Jade folded another 39 paper balls and Gem folded another 20. At the end of the two days, Jade made
79 of the total number of balls. What was the number of paper balls that Gem folded?
|
Jade |
Gem |
Difference |
Before |
1 u + 56 |
1 u |
56 |
Change |
+ 39 |
+ 20 |
|
After |
1 u + 95 |
1 u + 20 |
75 |
Comparing between Jade and Gem in the end |
7 p |
2 p |
5 p |
Difference between the number of paper balls that Jade and Gem folded in the end is repeated.
Difference between the number of paper balls that Jade and Gem folded in the end
= 7 p - 2 p
= 5 p
Difference between the number of paper balls that Jade and Gem folded in the end
= (1 u + 95) - (1 u + 20)
= 1 u + 95 - 1 u - 20
= 95 - 20
= 75
5 p = 75
1 p = 75 ÷ 5 = 15
Number of paper balls that Gem folded
= 2 p
= 2 x 15
= 30
Answer(s): 30