PSLE Abi and Marion folded paper balls over two days. On Tuesday, Abi folded 9 paper balls more than Marion. On Wednesday, Abi folded another 32 paper balls and Marion folded another 5. At the end of the two days, Abi made
710 of the total number of balls. What was the number of paper balls that Marion folded?
|
Abi |
Marion |
Difference |
Before |
1 u + 9 |
1 u |
9 |
Change |
+ 32 |
+ 5 |
|
After |
1 u + 41 |
1 u + 5 |
36 |
Comparing between Abi and Marion in the end |
7 p |
3 p |
4 p |
Difference between the number of paper balls that Abi and Marion folded in the end is repeated.
Difference between the number of paper balls that Abi and Marion folded in the end
= 7 p - 3 p
= 4 p
Difference between the number of paper balls that Abi and Marion folded in the end
= (1 u + 41) - (1 u + 5)
= 1 u + 41 - 1 u - 5
= 41 - 5
= 36
4 p = 36
1 p = 36 ÷ 4 = 9
Number of paper balls that Marion folded
= 3 p
= 3 x 9
= 27
Answer(s): 27