PSLE Jaslyn and Hilda folded paper stars over two days. On Tuesday, Jaslyn folded 12 paper stars more than Hilda. On Wednesday, Jaslyn folded another 23 paper stars and Hilda folded another 11. At the end of the two days, Jaslyn made
58 of the total number of stars. What was the number of paper stars that Hilda folded?
|
Jaslyn |
Hilda |
Difference |
Before |
1 u + 12 |
1 u |
12 |
Change |
+ 23 |
+ 11 |
|
After |
1 u + 35 |
1 u + 11 |
24 |
Comparing between Jaslyn and Hilda in the end |
5 p |
3 p |
2 p |
Difference between the number of paper stars that Jaslyn and Hilda folded in the end is repeated.
Difference between the number of paper stars that Jaslyn and Hilda folded in the end
= 5 p - 3 p
= 2 p
Difference between the number of paper stars that Jaslyn and Hilda folded in the end
= (1 u + 35) - (1 u + 11)
= 1 u + 35 - 1 u - 11
= 35 - 11
= 24
2 p = 24
1 p = 24 ÷ 2 = 12
Number of paper stars that Hilda folded
= 3 p
= 3 x 12
= 36
Answer(s): 36