PSLE Xylia and Abi folded paper stars over two days. On Wednesday, Xylia folded 50 paper stars more than Abi. On Thursday, Xylia folded another 26 paper stars and Abi folded another 20. At the end of the two days, Xylia made
710 of the total number of stars. What was the number of paper stars that Xylia folded?
|
Xylia |
Abi |
Difference |
Before |
1 u + 50 |
1 u |
50 |
Change |
+ 26 |
+ 20 |
|
After |
1 u + 76 |
1 u + 20 |
56 |
Comparing between Xylia and Abi in the end |
7 p |
3 p |
4 p |
Difference between the number of paper stars that Xylia and Abi folded in the end is repeated.
Difference between the number of paper stars that Xylia and Abi folded in the end
= 7 p - 3 p
= 4 p
Difference between the number of paper stars that Xylia and Abi folded in the end
= (1 u + 76) - (1 u + 20)
= 1 u + 76 - 1 u - 20
= 76 - 20
= 56
4 p = 56
1 p = 56 ÷ 4 = 14
Number of paper stars that Xylia folded
= 7 p
= 7 x 14
= 98
Answer(s): 98