PSLE
Gem and Sabrina folded paper balls over two days. On Monday, Gem folded 62 paper balls more than Sabrina. On Tuesday, Gem folded another 14 paper balls and Sabrina folded another 1. At the end of the two days, Gem made ⁷₉ of the total number of balls. What was the number of paper balls that Gem folded?

	Gem	Sabrina	Difference
Before	1 u + 62	1 u	62
Change	+ 14	+ 1
After	1 u + 76	1 u + 1	75
Comparing between Gem and Sabrina in the end	7 p	2 p	5 p

Difference between the number of paper balls that Gem and Sabrina folded in the end is repeated.

Difference between the number of paper balls that Gem and Sabrina folded in the end
= 7 p - 2 p
= 5 p

Difference between the number of paper balls that Gem and Sabrina folded in the end
= (1 u + 76) - (1 u + 1)
= 1 u + 76 - 1 u - 1
= 76 - 1
= 75

5 p = 75

1 p = 75 ÷ 5 = 15

Number of paper balls that Gem folded
= 7 p
= 7 x 15
= 105

Answer(s): 105